10a^2=5a

Solution for 10a^2=5a equation:

10a^2=5a

We move all terms to the left:

10a^2-(5a)=0

a = 10; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·10·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*10}=\frac{0}{20}
=0
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*10}=\frac{10}{20}
=1/2
$